2x^2-3x+3x-26=180

Solution for 2x^2-3x+3x-26=180 equation:

2x^2-3x+3x-26=180

We move all terms to the left:

2x^2-3x+3x-26-(180)=0

We add all the numbers together, and all the variables

2x^2-206=0

a = 2; b = 0; c = -206;
Δ = b2-4ac
Δ = 02-4·2·(-206)
Δ = 1648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1648}=\sqrt{16*103}=\sqrt{16}*\sqrt{103}=4\sqrt{103}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{103}}{2*2}=\frac{0-4\sqrt{103}}{4}
=-\frac{4\sqrt{103}}{4}
=-\sqrt{103}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{103}}{2*2}=\frac{0+4\sqrt{103}}{4}
=\frac{4\sqrt{103}}{4}
=\sqrt{103}
$